Answer:
147 J
Explanation:
Step 1: Given and required data
- Specific heat capacity of zinc (c): 0.377 J/g.°C
- Initial temperature (T₁): 98.1 °C
- Final temperature (T₂): 37.4 °C
Step 2: Calculate the amount of heat (Q) lost by the piece of zinc
We will use the following expression.
Q = c × m × (T₂ - T₁)
Q = (0.377 J/g.°C) × 6.41 g × (37.4 °C - 98.1 °C) = -147 J
The piece of zinc will lose 147 J in the form of heat.
