23-11-2016
Mathematics

contestada

(8x^3y^3z^4)(7x^6z^6)

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shakira3 shakira3

23-11-2016

First you multiple 8x times 7x and get 56x and since 3y doesn't have another y so u Leave tht as 3y then you multiply 3z times 6z and get 18z then you multiply 4 times 6 and get 24 (56x^3y)(18z^24)

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