A. (1, 0) and (–6, –28)
B. (1, 20) and (6, 0)
C. (1, 0) and (6, 20)
D. no solution
Correct answer is C.
[tex]y=x^2-3x+2 \\y=4x-4\\ \\4x-4=x^2-3x+2 \\x^2-7x+6=0 \\x^2-6x-x+6=0 \\x(x-6)-(x-6)=0 \\(x-6)(x-1)=0 \\x=6\,\text{ or }x=1 \\y=4\times 6-4=20 \,\text{ or }y=4\times 1-4=0 \\ \\(6,20)\,\text{ and }(1,0)[/tex]
