jdb7kDiso2rricr jdb7kDiso2rricr

24-11-2016
Chemistry

contestada

A 0.4243-g sample of CaCO 3 is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL
in a volumetric flask.How many moles of CaCO 3 are used (formula mass = 1 00.1 )?

Respuesta :

scme1702 scme1702

26-11-2016

Moles = mass / Mr
= 0.4243 / 100.1
= 4.239 x 10⁻³ mole of CaCO₃

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