Rectangle A has a length of 2x + 6 and a width of 3x. Rectangle B has a length of x + 2 and an area of 12 square units greater than Rectangle A’s area. What is a simplified expression for the width of Rectangle B?
So here is how you solve for the answer. Firstly, you solve for the Area of Rectangle A. The formula for Area is Length x width. So A = (2x + 6)(3x) and the result is: 6x^2 + 18x Now, let y be the width of rectangle B. (x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1) So the final answer would be width is 6x + 6. The answer is the third option. Hope this answer helps.
