Answer:
[tex]2.18\%[/tex]
Explanation:
Volume of isopropyl alcohol = 24 mL
Volume of water = 1.1 L
Percentage of isopropyl alcohol is given by
[tex]\dfrac{\text{Volume of isopropyl alcohol}}{\text{Volume of isopropyl alcohol+Volume of water}}\times 100\\= \dfrac{24\times 10^{-3}}{1.1+2.4\times 10^{-3}}\times 100\\ =2.18\%[/tex]
The percent by volume of isopropyl alcohol in the given solution is [tex]2.18\%[/tex].
