Answer:
[tex]P_2=1971.2torr[/tex]
Explanation:
Hello there!
In this case, by recalling the Gay-Lussac's gas law, as a directly proportional relationship between pressure and temperature, we can write:
[tex]\frac{P_2}{T_2} =\frac{P_1}{T_1}[/tex]
Thus, by solving for the required final pressure, in atmospheres first, we solve for P2 as follows:
[tex]P_2 =\frac{P_1T_2}{T_1}\\\\P_2=\frac{2.25atm*317K}{275K}\\\\P_2=2.59atm[/tex]
Which in Torricelli is:
[tex]P_2=2.59atm *\frac{760torr}{1atm}\\\\P_2=1971.2torr[/tex]
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