jmoncayo9179 jmoncayo9179
  • 23-05-2021
  • Physics
contestada

What will be the change in "velocity" of a 991 kg car if a force of 31,770 N is applied to it for 0.4 seconds?

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nuuk nuuk
  • 23-05-2021

Answer: [tex]12.82\ m/s[/tex]

Explanation:

Given

Mass of car [tex]m=991\ kg[/tex]

Force applied [tex]F=31,770\ N[/tex]

time period [tex]t=0.4\ s[/tex]

Acceleration associated with car

[tex]\Rightarrow a=\dfrac{F}{m}\\\\\Rightarrow a=\dfrac{31770}{991}\\\\\Rightarrow a=32.05\ m/s^2[/tex]

Acceleration is the change in velocity w.r.t time

[tex]\Rightarrow a=\dfrac{\Delta v}{\Delta t}\\\\\Rightarrow 32.05=\dfrac{\Delta v}{0.4}\\\\\Rightarrow \Delta v=12.82\ m/s[/tex]

thus, the change in velocity is [tex]12.82\ m/s[/tex]

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