Answer:
A‘‘ (1,6)
Step-by-step explanation:
after a reflection about a horizontal line the x coordinates remain the same
the middle point of the segment AA’ lies on the line so it has y = -1
so we have
(y+y’)/2 = -1
y’ = -2 -y
y‘ = -2 -2 = -4
so A‘ (1,-4)
we can use the same reasoning to find the reflection about y = 1
x‘ = x
(y + y’)/2 = 1
y‘ = 2+4
y’ = 6
A‘‘(1,6)
