Answer:
B = 2.9 mT
Explanation:
Given that,
The distance between the wires, r = 2 cm
Distance halfway between them d = 1 cm = 0.01 m
The current in the wires, I = 145 A
We need to find the strength of the magnetic field they produce, halfway between them. The formula for the magnetic field in the wire is given by :
[tex]B=\dfrac{\mu_o I}{2\pi d}\\\\B=\dfrac{4\pi \times 10^{-7}\times 145}{2\pi \times 0.01}\\\\B=2.9\ mT[/tex]
So, the required magnetic field is 2.9 mT.
