Answer:
Explanation:
no. of moles of butane = 5.87g / 58.124 = 0.1009mol
since O2 is excess, limiting reagent is butane
from the equation, 2 moles of butane will reacted to produce water = 10 moles
therefore, 0.1009 moles of butane produced water = (0.1009 x 5) = 0.5050 moles
Weight of H2O formed = 0.5050 x 18.015 = 9.10 grams
