Answer:
option C , D , E
Step-by-step explanation:
[tex]\sqrt{\frac{1}{16}} = \frac{1}{4} => not \ irrational\\\\\sqrt{\frac{1}{4}} = \frac{1}{2} => not \ irrational\\\\\sqrt{\frac{1}{2}} = > \ irrational\\\\\sqrt{\frac{1}{10}} =>\ irrational\\\\\sqrt{\frac{1}{8}} =>\ irrational\\\\[/tex]
