Answer:
The slope of the tangent line at x = 1 is -25.
Step-by-step explanation:
We are given the function:
[tex]f(x)=-7x^3-8x+2x^2[/tex]
And we want to find the slope of the tangent line at x = 1.
The slope of the tangent line at a point for a function is given by its derivative. Find the derivative of the function:
[tex]f'(x)=-21x^2+4x-8[/tex]
Then the slope of the tangent line at x = 1 is:
[tex]f'(1)=-21(1)^2+4(1)-8=-25[/tex]
