A student threw a ball horizontally out of a window 5.9 meters above the ground. It
was caught by another student who was 14.6 meters away. What was the horizontal
velocity of the ball?

A student threw a ball horizontally out of a window 59 meters above the ground It was caught by another student who was 146 meters away What was the horizontal class=

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Answer:

Explanation:

In the absence of air resistance, the horizontal velocity will not change.

Assuming the ball was caught at ground level,

The time of flight is

t = √(2s/a) = √(2(5.9) / 9.8) = 1.1 s

the horizontal velocity is

vx = 14.6/1.1 = 13.3 m/s

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