Answer: 7.13 L
Explanation:
What is the volume of 1.0 mole of gas at a pressure of 3.12 ATM and a temperature of 270K
AT STP OF 1 ATM OF PRESSURE AND 273K ONE MOLE OF GAS OCCUPIES 22.4 L
WE HAVE MORE THAN TRIPPLED THE PRESSURE AND SLIGHTLY LOWERED THE TEMP
THE NEW VOLUME WILL BE 22.4 x (1/3.12) x 270/273 =7.13 L
