tanijahtanijah tanijahtanijah

21-11-2021
Mathematics

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What are the zero(s) of the function f(x) = 4x^2 - 36x/ x - 9

A) x= -9
B) x=0
C) x=9
D) x = 0 and x = 9

What are the zeros of the function fx 4x2 36x x 9 A x 9 B x0 C x9 D x 0 and x 9 class=

Respuesta :

21-11-2021

To find -intercept/zero, substitute
So
0=4x^2-36x / 9-x
Now x should be #9 bcz 9-9=0
So
0=4x x(x-9)/x-9
0=4x
X=0

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