Respuesta :

It's a isosceles triangle

For any triangle

[tex]\\ \tt\longmapsto cos\theta=\dfrac{Base}{Hypotenuse}[/tex]

  • We need H

[tex]\\ \tt\longmapsto cos30=\dfrac{6}{H}[/tex]

[tex]\\ \tt\longmapsto H=\dfrac{6}{cos30}[/tex]

[tex]\\ \tt\longmapsto H=\dfrac{6}{0.86}[/tex]

[tex]\\ \tt\longmapsto H=6.9\approx 7ft[/tex]

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