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24-02-2022
Chemistry

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What is [H+] in a solution with a pH = 1.82?

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24-02-2022

[tex]\\ \tt\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \tt\Rrightarrow 1.82=-log[H^+][/tex]

[tex]\\ \tt\Rrightarrow log[H^+]=-1.82[/tex]

[tex]\\ \tt\Rrightarrow [H^+]=10^{-1.82}[/tex]

[tex]\\ \tt\Rrightarrow [H^+]=0.015M[/tex]

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