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Circle P has a radius of 5 centimeters. Point Q lies on circle P, and the equation of PQ←→ is y=25x+3. Which equation could be the equation of a line tangent to circle P at point Q?

Respuesta :

5x+2y=7 that would be the correct equation

The required equation of the tangent is 5x+2y=6.

Radius of the circle = 5cm
Equation of the PQ, y =2/5x+3
Equation of tangent at Q to determine.

What is the equation?

The equation is the values of two expressions that are equal.

Here, tangent to the circle at Q.
y = -(1/m)x+c
y = -(5/2)x + 3
y = -5x/2 +3
5x + 2y = 6

Thus, the required equation of the tangent is 5x+2y=6.

Learn more about the equation here:
https://brainly.com/question/10413253

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