Support that P(e)=0.76,P(F)=0.45,and P(E and F)=0.32. What is P (E or F)?

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26-01-2015
Physics

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Support that P(e)=0.76,P(F)=0.45,and P(E and F)=0.32. What is P (E or F)?

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AL2006 AL2006 · Answer 1 · 2015-01-26T19:32:00+01:00

The probability of (E and F) = P(e) times P(f) = 0.76 x 0.45 = 0.342 .

The probability of (e OR f) =

   1 - P(not e AND not f) =

   1 - P(not e) x P(not f) =

   1 - (1 - 0.76) x (1 - 0.32) =

   1 - ( 0.24 )   x   ( 0.68 ) = 1 - 0.1632 = 0.8368.