zaimovicsven23 zaimovicsven23
  • 22-04-2022
  • Mathematics
contestada

need help with question 16

need help with question 16 class=

Respuesta :

devishri1977
devishri1977 devishri1977
  • 22-04-2022

Answer:

C)

Step-by-step explanation:

u =  x + 1

u - 1 = x

[tex]\int\limits {\dfrac{x}{\sqrt{x+1}}} \, dx = \int\limits {\dfrac{u-1}{\sqrt{u}}} \, du \\\\[/tex]

                   [tex]=\int {\left(\dfrac{u}{u^{\frac{1}{2}}}-\dfrac{1}{u^{\frac{1}{2}}} \right )\, du \\\\ = \int {u^{1-\frac{1}{2}}-1*u^{\frac{-1}{2}}} \, du\\\\ =\int {(u^{\frac{1}{2}}-u^{\frac{-1}{2}})} \, du[/tex]

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