rosalindacostantin23 rosalindacostantin23

24-04-2022
Chemistry

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36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of
product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Respuesta :

24-04-2022

Answer:

4 mol MgO

Explanation:

convert the limiting reactant to product by using dimensional analysis in order to see how many moles total can be created of the product

4 mol Mg x [tex]\frac{2 mol MgO}{2 mol Mg}[/tex] = 4 mol MgO

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