Step-by-step explanation:
[tex] \frac{1}{4} (5y + 4) = \frac{1}{3}(2y - 1) \\ \frac{5y + 4}{4} = \frac{2y - 1}{3} \\ 3(5y + 4) = 4(2y - 1) \\ 15y + 12 = 8y - 4 \\ 15y - 8y = - 4 - 12 \\ 7y = - 16 \\ y = \frac{ - 16}{7} \\ y = - 2.28[/tex]
Hope it helps
