jordanliwanag jordanliwanag

24-05-2022
Chemistry

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How many mL of 0.55 M CaCl2 have 18.67 g of CaCl2 in them?

Respuesta :

armellebk02 armellebk02

24-05-2022

Answer:

305.8mL

Explanation: l believe first we get the moles of CaCl2 by dividing the given mass to the molar mass. We than find the volume by manipulating (make v the subject of the formula) the formula c= n÷v.

n(CaCl2)= m/M=(18.67g)÷(110.98g/mol)

=0.16822mol

c=n/v

v= n/c = (0.16822mol)÷ (.55M) = 0.3058L = 305.305.8ml

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