emanuel20971
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Lucite contains 59.9 g C, 8.06 g H,
and 32.0 g O. You want to
determine the empirical formula.
How many moles of H are in the
sample?

{?} mol H

Respuesta :

kmburton
You start by finding the mol of each

59.9g C x (mol C / 12.01 g C) = 4.98 mol C
8.06g H x (mol H / 1.00 g H) = 8.06 mol H
32.0 g O x (mol O / 16.0 g O) = 2 mol O

So when you set it up you have
C4.98 H8 O2

You divide each by the smallest mol. The smallest mol is 2

C2 H4 O2.5

However you can’t have half a mol in the empirical formula. If the value ends in 0.5, you multiply everything by 2

You’re left with

C2H8O5

The EMPIRICAL formula for lucite is C2H8O5

Note empirical is not the same as chemical formula.

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