vanessasumampouw938 vanessasumampouw938

23-06-2022
Mathematics

contestada

PLS HELP!!

Find the zeros of y=x² - 6x-4 by completing the square.
O A. x= 3± √13
OB. x = 3± √5
O C. x = -3± √13
OD. x = ±3

Respuesta :

alexanderorangeguy alexanderorangeguy

23-06-2022

Answer:

A

Step-by-step explanation:

y = x² - 6x - 4

(x - 3)² - 3² - 4 = 0

(x - 3)² - 13 = 0

(x - 3)² = 13

x - 3 = ±√13

x = 3 ± √13

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isabellagotay1 isabellagotay1

23-06-2022

It’s A I just did this

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