e15lefty e15lefty
  • 23-08-2022
  • Mathematics
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If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?

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amccarver1326
amccarver1326 amccarver1326
  • 23-08-2022

Answer:

-2

Step-by-step explanation:

x = 3 + bi,  |x|2 = 13

⇒  |x|2 = 13

|x|2 = 32 + b2

13 = 9 + b2

13 - 9 = b2

b2 = 4

b = 2, -2

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