[tex]\sin \theta=\frac{opposite}{hypotenuse}[/tex]
From the figure given, if theta = A
opposite = 28 and hypotenuse =53
substitute the values into the formula
[tex]\sin A=\frac{28}{53}[/tex]
[tex]\cos A=\frac{adjacent}{\text{hypotenuse}}[/tex][tex]\cos A=\frac{45}{53}[/tex][tex]\tan \theta=\frac{opposite}{adjacent}[/tex][tex]\tan A=\frac{28}{45}[/tex]
