Given:
The function is,
[tex]y=3x^3-9x^2[/tex]
To find the x intercept set y=0,
[tex]\begin{gathered} y=3x^3-9x^2 \\ 3x^3-9x^2=0 \\ x^2(3x-9)=0 \\ \Rightarrow x^2=0,3x-9=0 \\ x=0,3x=9 \\ x=0,x=\frac{9}{3} \\ x=0,x=3 \end{gathered}[/tex]
So, x-intercepts are ( 0 , 0 ), ( 3, 0 ).
Now to find y-intercepts set x=0.
[tex]\begin{gathered} y=3x^3-9x^2 \\ y=3(0)-9(0) \\ y=0 \end{gathered}[/tex]
y- intercept is ( 0 ,0 )
Answer: option e)
