Calculating the sine, cosine and tangent of the angle pi/6 (that is, 30°), we have that:
[tex]\begin{gathered} \sin (\frac{\pi}{6})=\frac{1}{2}_{} \\ \cos (\frac{\pi}{6})=\frac{\sqrt[]{3}}{2}_{} \\ \tan (\frac{\pi}{6})=\frac{\sin(\frac{\pi}{6})}{\cos(\frac{\pi}{6})}=\frac{\frac{1}{2}}{\frac{\sqrt[]{3}}{2}}=\frac{1}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3} \end{gathered}[/tex]