Due to the car goes around the trajectory without sliding, then. it is necessary that centripetal force equals the friction force.
Then, we have:
Fc = Fr
where,
Fc = m(v^2/R) centripetal force
Fr = μN = μ*m*g friction force
Then, by replacing the precious expressions we obtain:
m(v^2/R) = μ*m*g
And by solving for v:
[tex]v=\sqrt[]{\mu\cdot g\cdot R}[/tex]where,
μ = 1.00
g = 9.8 m/s^2
R = 70.0 m
By replacing we get:
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