MaxelK529864 MaxelK529864

25-10-2022
Physics

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2200 J of work was done in 10 s. What is the amount of power?

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AdalinaZ12505 AdalinaZ12505

25-10-2022

We will have that the power will be:

[tex]\begin{gathered} P=\frac{W}{\Delta t}\Rightarrow P=\frac{2200J}{10s} \\ \\ \Rightarrow P=220J/s\Rightarrow P=220W \end{gathered}[/tex]

So, the power was 220 Watts.

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