We need to convert the units:
• milliliter to liter;
,• second to hour.
Since each milliliter (mL) is the thousandth part of one liter (L), we have:
mL = 0.001 L
Also, since each hour (h) has 60 minutes (min), and each minute has 60 seconds (s), we have:
1 h = 60 min = 60 * 60 s = 3600 s
s = (h/3600)
Now, we can rewrite the rate of the leak as follows:
[tex]\frac{0.5mL}{s}=\frac{0.5\cdot0.001L}{\frac{1}{3600}h}=\frac{0.0005L}{h}\cdot3600=\frac{1.8L}{h}[/tex]
