Respuesta :
To find the number of term, we will use the formula;
[tex]U_{n\text{ = }}a+(n-1)d[/tex]when n= 1
[tex]U_1=\text{ 3 + (1-1)5}[/tex][tex]=\text{ 3+0}=3[/tex]for the second term
n = 2
[tex]U_2=\text{ 3 + (2-1)5}[/tex]= 3 + 5
=8
For n= 3
[tex]U_3=3+\text{ (3-1)5}[/tex]=3 + 2(5)
=3 + 10
=13
For n=4
[tex]U_4=3+(4-1)5[/tex]=3+3(5)
= 3 + 15
= 18
For n= 5
[tex]U_5=3+(5-1)5[/tex]= 3 + 4(5)
= 3 + 20
= 23
Therefore, the terms; 3, 8, 13, 18 and 23
