Since the triangle is dilated, the sides of the original triangle are stretched. Since J'K' is the length of one side of the triangle after the dilation, we have that:
[tex]\begin{gathered} J^{\prime}K^{\prime}=\frac{4}{3}JK,J^{\prime}K^{\prime}=13.5 \\ \Rightarrow13.5=\frac{4}{3}JK \\ \Rightarrow JK=\frac{3\cdot13.5}{4}=10.125 \end{gathered}[/tex]
Then, the answer is 10.125
