Solution
A line passes the points (-1, 9) and the slope = -6,
slope = -6
[tex]m=-6[/tex]
Let a line a slope
m
and passes through the point (x_1,y_1),
then the point-slope form of the straight line is
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ at\text{ points \lparen1,-9\rparen} \end{gathered}[/tex][tex]\begin{gathered} y_1=9 \\ x_1=-1 \\ y-9=-6(x--1) \\ y-9=-6(x+1) \\ y-9=-6x-6 \\ y=-6x-6+9 \\ y=-6x+3 \end{gathered}[/tex]
Therefore the equation of the line is
[tex]y=-6x+3[/tex]
