TheGhettoPug TheGhettoPug

23-02-2017
Mathematics

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The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

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abroderick2020 abroderick2020

23-02-2017

let the numbers be 2n-2,2n,2n + 2 then sum of squares will be 12 n ^2 + 8 = 116 which implies n = 3.numbers are 4,6,8

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Аноним Аноним

23-02-2017

5 6 7 or -7, -6, -5....................

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