acsebar acsebar

24-02-2017
Chemistry

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How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

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NathalyN NathalyN

24-02-2017

5.4 M = moles of solute / 1.50 L

Multiply both sides by 1.50 L to isolate moles of solute on the right.

8.1 mol = moles of solute

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jadyndarnick0 jadyndarnick0

29-11-2018

8.1 mol KCI

This would be the answer.

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