A horizontal spring has a 0.25kg block attached to it. The spring is compressed 23cm. At this point the force of friction and the force on the spring are in balance. Determine the spring constant if the coefficient of static friction between the block and surface is 0.41.

Respuesta :

Force of friction = uN = umg
Force by the spring = kx

If the forces are in balance they are equal
umg = kx
0.41(0.25)(9.8) = k(0.23)
k = 4.367 N/m