22-03-2017
Mathematics

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This how do I get the awnser

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22-03-2017

3)
m<1 = 59
m<2 = 90 - 59 = 31
m<3 = 59
m<4 = m<2 = 31
m<5 = m<2 = 31
m<6 = m<1 = 59
m<7 = 180 - (31 +31) = 180 - 62 = 118
m<8 = 180 - 118 = 62

4)
m<BCD = 90
m<ABD = m<BDC = 16
m<CBE =90 - 16 = 74
m<ADE = m<CBE = 74
m<AEB = m<DEC = 180 - (16+16) = 180 - 32 = 148
m<DEA = 180 - 118 = 32

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