Respuesta :

grace5121
No solution is the answer


soooobored
[tex]6 \sin \theta - 3 \csc \theta=0 6\sin ^2 \theta - 3=0 2 \sin ^2 \theta -1=0 2 \sin ^2 \theta =1 \sin ^2 \theta = \frac{1}{2} \sin \theta = \sqrt{\frac{1}{2}} \sin \theta = \frac{{\sqrt{2}}}{2} [/tex]