stoichiometry2 stoichiometry2

26-04-2017
Chemistry

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7.8g of dioxide would be produced from how many moles of potassium chlorate

Respuesta :

06-05-2017

2KClO₃ ⇒ 2KCl + 3O₂
2mol : 3mol
245,1g : 95,94g
x : 7,8g

x = 7,8g*245,1g / 95,94g = 19,93g

1mol of KClO₃ --------- is --------- 122,55g
x mol --------- is --------- 19,93g

x = 19,93g*1mol / 122,55g = 0,158mol

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