Answer:
[tex]y=(x+3)^{2}-6[/tex]
Step-by-step explanation:
Let's find the answer using the following method:
The original quadratic function is [tex]f(c)=x^{2}+6x+3[/tex]
The vertex form of a quadratic equation is:
[tex]y=(x-h)^{2}+k[/tex]
where (h,k) is the vertex which can be found as:
[tex]h=\frac{-b}{2a} =\frac{-6}{2*1}=-3\\h=f(h)=(-3)^{2}+(6*(-3))+3 = -6[/tex]
So the vertex form is:
[tex]y=(x+3)^{2}-6[/tex]
