Respuesta :

ghanami
hello : 
x²- y = 3 ...(1)
 x - y = -3 ...(2)
by (2) : y = x+3
subqct in (1) : x²-x-3 = 3
x²-x-6 =0
(x+2)(x-3) = 0
x+2 =0 or x-3 =0
x=-2 or x=3
if x = -2   y = -2+3 = 1
if x=3      y =3+3 = 6
two solutions : ( -2, 1) , (3,6)

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