Respuesta :

Move all terms to the left of equal with changed sign

x²-5x-2 = 0

Solve with x₁,₂ = (-b±√Δ)/2a

Δ = b²-4ac

call a (1)x², b -5 and c -2

x1,2 = (-(-5)±√(-5)²-4*1*(-2))/2*1

x1,2 = (5±√25+8)/2

x1,2 = (5±√33)/2

x1 = (5+√33)/2

x2 = (5-√33)/2
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Answer:

The answer has a positive 5 and 33.

Step-by-step explanation:

I used a calculator.

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