Answer: (0, 0)
Step-by-step explanation:
Given the equation of the hyperbola: 4y² = x² + 1
4(0)² = x² + 1
0 = x² + 1
x² = -1
4y² = 0² + 1
4y² = 1
y² = 1/4
y = ±1/2
Midpoint = ( (x₁ + x₂)/2 , (y₁ + y₂)/2 )
Midpoint = ( (0 + 0)/2 , (1/2 + (-1/2))/2 )
Midpoint = (0, 0)
