Answer:
D
Step-by-step explanation:
using the property of logarithms
• [tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
given
ln(3x + 2) = 4
[ Note that ln = [tex]log_{e}[/tex] ] , then
3x + 2 = [tex]e^{4}[/tex] ( subtract 2 from both sides )
3x = [tex]e^{4}[/tex] - 2 ( divide both sides by 3 )
x = [tex]\frac{e^4-2}{3}[/tex]
