[tex]\bf \begin{array}{ccll}
stones&lbs\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{14}&1\\\\
\frac{3}{4}&p
\end{array}\implies \cfrac{\quad \frac{1}{14}\quad }{\frac{3}{4}}=\cfrac{1}{p}\implies \cfrac{1}{14}\cdot \cfrac{4}{3}=\cfrac{1}{p}
\\\\\\
\cfrac{2}{21}=\cfrac{1}{p}\implies p=\cfrac{21\cdot 1}{2}\implies p=\cfrac{21}{2}\implies p=10\frac{1}{2}[/tex]
