jacesmokesloud6177 jacesmokesloud6177
  • 25-12-2017
  • Chemistry
contestada

What is the empirical formula of a compound that breaks down into 4.12g of n and 0.88g of h? answers?

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W0lf93
W0lf93 W0lf93
  • 07-01-2018
We know the number of grams of each element, so the first step is to convert that into moles. So for nitrogen, 4.12g N x (1 mol N/14 g N) = 0.29 moles of N. For hydrogen, .88 g H x (1 mol H/1.01 g N) = 0.87 moles of H. The next step is to divide each by the smallest number of moles found. In this case, that is the .29 moles of N. So, for N, 0.29/0.29 = 1. For H, .88/.29 = 3. There is no need for further rounding, so the empirical formula is H3N1.
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barakauzuri barakauzuri
  • 10-05-2019

Answer:

NH3

Explanation:

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