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  • 25-11-2015
  • Mathematics
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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1.

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Аноним Аноним
  • 25-11-2015
Vertex: (-5, 2)
Standard form of a vertical parabola
(x - h)^2 = 4p (y-k)
(x - (5))^2 = 4p (y -2)
(x + 5)^2 = 4p (y-2)
p is the distance between the vertex and either the focus or the directrix:
p = 3

Final equation:
(x +5)^2 = 4*3 (y-2)
(x + 5)^2 = 12 (y-2)
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